3.Prove that the following are irrationals : ii)7√5
(ii) 7√5
Assume that 7√5 is rational.
Dividing both sides by 7 (a rational number):
√5 becomes rational.
This is a contradiction.
Therefore, 7√5 is irrational.
Assume that 7√5 is rational.
Dividing both sides by 7 (a rational number):
√5 becomes rational.
This is a contradiction.
Therefore, 7√5 is irrational.